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### Messages - Maria-Clara Eberlein

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1
##### Test 1 / Re: 2020TT1 Deferred Sitting #1
« on: October 14, 2020, 09:58:17 PM »
Oh okay that makes sense thank you so much!

2
##### Test 1 / Re: 2020TT1 Deferred Sitting #1
« on: October 14, 2020, 08:51:11 PM »
Thank you! How do we know the period is pi?

3
##### Test 1 / 2020TT1 Deferred Sitting #1
« on: October 14, 2020, 04:44:15 PM »
In the last line of a) why do we add pi*m (as opposed to 2pi*m)?

How do we find the values in b) ?

4
##### Test 1 / Re: 2020 Night Sitting #1
« on: October 14, 2020, 03:54:06 PM »
Okay makes sense, thank you!

5
##### Test 1 / Re: 2018 test 1 variant C 2b
« on: October 14, 2020, 03:53:24 PM »
Ok if it has a typo then that makes sense, thank you!

6
##### Test 1 / Re: 2020S-TT1 Q1
« on: October 14, 2020, 03:52:26 PM »
This is how I got the answer, hope this helps!

7
##### Test 1 / 2020 Night Sitting #1
« on: October 14, 2020, 01:03:24 PM »
When I solve the equation w^2+w+1=0, I got two complex roots instead of two real roots. Is there an i missing from the value of w?

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##### Test 1 / Re: spring 2020 test main sitting question 2
« on: October 13, 2020, 05:29:33 PM »
Without actually expanding the numerator and denominator, you can see that they would have the same degree (5) and so the limit is the leading coefficient of the numerator (1) divided by the leading coefficient of the denominator (3), so 1/3.

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##### Test 1 / 2018 test 1 variant C 2b
« on: October 12, 2020, 05:16:22 PM »
How did we get from the second last to last line, in particular the calculation with (2n)! and (2n+2)! (See attachment)

10
##### Chapter 1 / 1.2 circles
« on: September 23, 2020, 07:27:50 PM »
When we have are asked to find the locus of |z-p|=|z-q|, can we immediately say the perpendicular bisector of the line segment joining p and q, or must we plug in z=x+iy and solve to get x=0?

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##### Chapter 1 / Solving roots of complex numbers
« on: September 20, 2020, 07:02:56 PM »
Suppose we want to solve for z=a+ib in an equation of the form z^n=w. After we find z in exponential representation, I am unsure of how to convert to z=a+ib form if theta is not one of the "special angles" we know the sin and cos of? Should we write z=rcos(theta)+i(rsin(theta)) without evaulating sin(theta) and cos(theta)?

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