MAT334--2020S > Chapter 3

3.1 question 5

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**Yan Zhou**:

$$f(z) = z^9 + 5z^2 + 3$$

I have difficulty in figuring out how f moves on $iy$.

The following is my steps.

$$f(iy) = iy^9 - 5y^2 + 3$$

y moves from R to 0. Im(f) > 0, f always lie in first or second quadrant.

f(0) = 3 on the real axis.

$$f(iR) = iR^9 - 5R^2 + 3$$

$$arg(f) = arctan(\frac{R^9}{-5R^2 + 3})$$

As R goes to $\infty$, arg(f) goes to $\frac{\pi}{2}$,

Then arg(f) changes from $\frac{\pi}{2}$ to 0, then $\Delta arg(f) = -\frac{\pi}{2}$

I am not sure about arctan part, should it goes to $\frac{\pi}{2}$ or $-\frac{\pi}{2}$

and if there is any other mistakes, thanks for pointing out!

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