### Author Topic: HA9-P5  (Read 2034 times)

#### Bruce Wu

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##### HA9-P5
« on: November 12, 2015, 09:42:55 PM »

#### Bruce Wu

• Sr. Member
• Posts: 57
• Karma: 0
##### Re: HA9-P5
« Reply #1 on: November 12, 2015, 09:43:09 PM »
Let $M$ and $R$ be the mass and radius of the Earth, respectively. If we assume that the Earth is a homogeneous sphere, then it has a constant density $\rho=\frac{3M}{4\pi R^3}$. For some radius $r<R$ from the centre of the Earth, all of the mass located at a radius greater than $r$ would not contribute anything to the gravitational field according to Newton's shell theorem. Therefore by Newton's law of gravity, the gravitational field at such an $r$ is $$\vec{g}=-\frac{GM_{enc}}{r^2}\hat{r}$$
Where $M_{enc}$ is the mass enclosed within the sphere of radius $r$.
$$M_{enc}=\rho\frac{4}{3}\pi r^3=M\frac{r^3}{R^3}$$ Finally
$$\vec{g}=-\frac{GM}{R^3}r\hat{r}$$
Which is proportional to $r$.