Toronto Math Forum
MAT2442020F => MAT244Lectures & Home Assignments => Chapter 4 => Topic started by: Jiayi Wang (Ivy) on November 17, 2020, 07:21:33 PM

I was working on the 2019FEP3, for the Problem3 of the Deferred section, I got C1=10e^(t)+10arctan(e^t)+C1, C2=4e^(2t)+4ln(e^(2t)+1)+C2
The answer shows C1=10e^(t)+5arctan(e^t)+C1, C2=4e^(2t)4ln(e^(2t)+1)+C2.
I was wondering if anyone got the same answer with me, thanks very much.

I get C1 = 10e^(t) + 10arctan(e^t) + C1 and C2 = 4e^(2t) + 4Ine^(2t)+1 + C2. I think there might be a typo here.

There could be misprints