Toronto Math Forum
MAT2442019F => MAT244Test & Quizzes => Quiz4 => Topic started by: Yuchen Cong on October 19, 2019, 05:11:25 PM

Question:
2y''+2y+1=0
Solution:
2r^{2}+2r+1=0
r=[2+((2)^{2}(4)(2)(1))^{(1/2)}]/2(2)
r=[2+(4)^{(1/2)}]/4
r=(1/2)+(1/2)i
λ=(1/2), µ=1/2
y(t)=C1e^{(1/2)t}cos(1/2)t+C2e^{(1/2)t}sin(1/2)t