Toronto Math Forum
MAT2442019F => MAT244Test & Quizzes => Quiz3 => Topic started by: Xuefeng Fan on October 11, 2019, 02:15:17 PM

hi everyone here is the quiz question find the general solution of the given differential equation
2y'' 3y' +y = 0
therefore 2r^2 3r + 1 = 0
therefore (2r1)(r1) = 0
R1 = 1/2 R2 = 1
therefore y = C1e^((1/2)t)+C2e^t