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Messages - shizhiwei

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Quiz-4 / Wrong post
« on: October 18, 2019, 02:25:37 PM »
Post the wrong content , ignore this post

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Quiz-4 / TUT0702 quiz4
« on: October 18, 2019, 02:11:17 PM »
find the general solution of the given diffrentiation equation

y''-6y'+9y=0

r^2-6r+9=0
(r-3)^2=0
r=3

the general solution is y=(C1)e^3t+(C2)e^3t

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Quiz-3 / Tut0702 quiz3
« on: October 11, 2019, 02:02:39 PM »
Find the general solution of the given differential equation:
4y'' - 9 y = 0

Solution:
4r^2 - 9 = 0
4r^2 = 9
r^2 = 9/4
r = +/- 3/2
r1 = 3/2
r2 = -3/2
Therefore, the general solution is y = C1e^3t/2 + C2e^-3t/2

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Quiz-2 / tut0702 quiz2
« on: October 04, 2019, 03:27:42 PM »
determine whether the equation is exact or not
((e^2)sin(y)−2ysin(x))−(3x−(e^x)sin(y))y′=0

let             M(x,y)=(e^x)sin(y)−2ysin(x)
N(x,y)=−3x+(e^x)sin(y)

simplify and we get    My(x,y)=(e^x)cos(y)−2sin(x)
Nx(x,y)=−3+(e^x)sin(y)

we can conclude that  My is not equal to Nx, therefore the diffrentiation equation is not exact

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