Author Topic: Quiz4 TUT5102  (Read 495 times)

Nuo Chen

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Quiz4 TUT5102
« on: October 18, 2019, 02:07:09 PM »
Find the general solution of the differential equation
$$
16 y^{\prime \prime}+24 y^{\prime}+9 y=0
$$

$$
\begin{array}{l}{16 r^{2}+24 r+9=0} \\ {(4 r+3)^{2}=0} \\ {r_{1}=r_{2}=-\frac{3}{4}} \\ {\therefore y=c_{1} e^{-\frac{3}{4} t}+C_{2} t e^{-\frac{3}{4} t}}\end{array}
$$