Author Topic: Tut 0202 QUIZ 4  (Read 817 times)

Jiwen Bi

  • Jr. Member
  • **
  • Posts: 7
  • Karma: 3
    • View Profile
Tut 0202 QUIZ 4
« on: October 18, 2019, 07:51:06 PM »
$The\,Chaacteristic\,eqution\,is:\\
4r^{2}+12r+9=0\\
the\,roots\,of\,this\,eqution\,is\\
r_{1,2}=\frac{-12\pm \sqrt{144-16*9}}{8}\\
=\frac{-12\pm 0}{8}\\
=-\frac{3}{2}\\
Result:y(t)=c_{1}e^{-\frac{3t}{2}}+c_{2}te^{-\frac{3}{2}}$