Toronto Math Forum

MAT244--2019F => MAT244--Test & Quizzes => Quiz-4 => Topic started by: Wusijia on October 18, 2019, 02:01:53 PM

Title: TUT0502 QUIZ4
Post by: Wusijia on October 18, 2019, 02:01:53 PM
\begin{equation*}
9y''+6y'+y=0
\end{equation*}
\begin{equation*}
9r^2+6r+1=0
\end{equation*}
\begin{equation*}
 (3r+1)^2=0
\end{equation*}
\begin{equation*}
r_1=r_2=-\frac{1}{3}\\
\end{equation*}
\begin{equation*}
y=C_1e^{-\frac{1}{3}t}+C_2te^{\frac{1}{3}t}
\end{equation*}