Toronto Math Forum
MAT244--2020F => MAT244--Lectures & Home Assignments => Chapter 4 => Topic started by: Jiayi Wang (Ivy) on November 17, 2020, 07:21:33 PM
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I was working on the 2019-FE-P3, for the Problem3 of the Deferred section, I got C1=10e^(-t)+10arctan(e^t)+C1, C2=-4e^(-2t)+4ln(e^(-2t)+1)+C2
The answer shows C1=10e^(-t)+5arctan(e^t)+C1, C2=-4e^(-2t)-4ln(e^(2t)+1)+C2.
I was wondering if anyone got the same answer with me, thanks very much.
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I get C1 = 10e^(-t) + 10arctan(e^t) + C1 and C2 = -4e^(-2t) + 4In|e^(2t)+1| + C2. I think there might be a typo here.
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There could be misprints