Author Topic: Transport Equation Derivation  (Read 476 times)

Yifei Hu

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Transport Equation Derivation
« on: January 18, 2022, 07:34:32 PM »
Can anyone help explain where does the Ut term in the second last line come from? Thanks

Victor Ivrii

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Re: Transport Equation Derivation
« Reply #1 on: January 19, 2022, 05:06:34 AM »
It would be really helpfull if you explained where you took this from (if online TextBook--then section and equation number, if lecture then which lecture and which part).

Yifei Hu

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Re: Transport Equation Derivation
« Reply #2 on: January 23, 2022, 10:17:29 PM »
Hi Professor Ivrii, this comes from Christopher's lecture #3 when he discussed transport equation, directly from his lecture notes #3 on top of page 2 : )

Victor Ivrii

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Re: Transport Equation Derivation
« Reply #3 on: January 24, 2022, 05:46:09 AM »
Then your best shot would be
  • either to ask during Prof Kennedy's Office hours
  • or to formulate the problem and define everything  (that is $u, v, S, \tilde{S}$) here by yourself without screenshots 
My guess that it is a continuity condition.