MAT334-2018F > Reading Week Bonus--sample problems for TT2

Term Test 2 sample P5

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Ye Jin:
I have modified but for |z|>5, the largest power I got is -2.

Victor Ivrii:
Calculate the coefficient at $z^{-2}$. The answer is rather obvious because $f(z)$ decays as $z^{-4}$ as $z\to \infty$

Ye Jin:

--- Quote from: Victor Ivrii on November 09, 2018, 10:04:59 AM ---Calculate the coefficient at $z^{-2}$. The answer is rather obvious because $f(z)$ decays as $z^{-4}$ as $z\to \infty$

--- End quote ---
So I should start from n=-1 because the coefficient is 0 when n=0?

Victor Ivrii:

--- Quote from: Ye Jin on November 09, 2018, 10:30:36 AM ---
--- Quote from: Victor Ivrii on November 09, 2018, 10:04:59 AM ---Calculate the coefficient at $z^{-2}$. The answer is rather obvious because $f(z)$ decays as $z^{-4}$ as $z\to \infty$

--- End quote ---
So I should start from n=-1 because the coefficient is 0 when n=0?

--- End quote ---
While starting from the term with $0$ coefficient is not technically an error, it is definitely a bad bad practice.

Ye Jin:

--- Quote from: Victor Ivrii on November 09, 2018, 10:39:24 AM ---
--- Quote from: Ye Jin on November 09, 2018, 10:30:36 AM ---
--- Quote from: Victor Ivrii on November 09, 2018, 10:04:59 AM ---Calculate the coefficient at $z^{-2}$. The answer is rather obvious because $f(z)$ decays as $z^{-4}$ as $z\to \infty$

--- End quote ---
So I should start from n=-1 because the coefficient is 0 when n=0?

--- End quote ---
While starting from the term with $0$ coefficient is not technically an error, it is definitely a bad bad practice.

--- End quote ---
And now is there any other mistake I have made?

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