Toronto Math Forum
MAT244--2019F => MAT244--Test & Quizzes => Quiz-4 => Topic started by: Jiwen Bi on October 18, 2019, 07:51:06 PM
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$The\,Chaacteristic\,eqution\,is:\\
4r^{2}+12r+9=0\\
the\,roots\,of\,this\,eqution\,is\\
r_{1,2}=\frac{-12\pm \sqrt{144-16*9}}{8}\\
=\frac{-12\pm 0}{8}\\
=-\frac{3}{2}\\
Result:y(t)=c_{1}e^{-\frac{3t}{2}}+c_{2}te^{-\frac{3}{2}}$