Author Topic: TUT 0202 QUIZ1  (Read 620 times)

Yijin Qiang

  • Jr. Member
  • **
  • Posts: 8
  • Karma: 2
    • View Profile
TUT 0202 QUIZ1
« on: September 27, 2019, 03:08:09 PM »
${y}'+y^{2}sin(x)= 0\\\frac{dy}{dx}= -y^{2}sin(x)\\dy=-y^{2}sin(x)dx\\-\int \frac{1}{y^{2}}dy=\int sin(x)dx\\-\frac{1}{y}=-cos(x)+C\\y=\frac{1}{cos(x)+C}$