Author Topic: QUIZ4 TUT 0502  (Read 634 times)

Xinyu Jing

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QUIZ4 TUT 0502
« on: October 19, 2019, 01:23:47 AM »
Find the general solution of the differential equation
𝑦″+2𝑦′+2𝑦=0


The characteristic equation of the given equation is:

$𝑟^{2}$+2𝑟+2=0

𝑟=$\frac{−𝑏±\sqrt{𝑏^{2}−4𝑎𝑐}}{2𝑎}$=$\frac{−2±\sqrt{-4}}{2}$=−1±𝑖

Then,
$𝑟_{1}$=−1+𝑖 $𝑟_{2}$=−1−𝑖


Therefore, the general solution of the given differential equation is:
𝑦=$𝑐_{1}𝑒^{−𝑡𝑐𝑜𝑠𝑡}+𝑐_{2}𝑒^{−𝑡𝑠𝑖𝑛𝑡}$