Toronto Math Forum
Welcome,
Guest
. Please
login
or
register
.
1 Hour
1 Day
1 Week
1 Month
Forever
Login with username, password and session length
News:
Home
Help
Search
Calendar
Login
Register
Toronto Math Forum
»
MAT244--2019F
»
MAT244--Test & Quizzes
»
Quiz-4
»
Quiz 4 TUT0202
« previous
next »
Print
Pages: [
1
]
Author
Topic: Quiz 4 TUT0202 (Read 7116 times)
Mengyuan Wang
Jr. Member
Posts: 6
Karma: 2
Quiz 4 TUT0202
«
on:
October 19, 2019, 04:46:15 PM »
4y'' + 12y' + 9y = 0
let y = e^rt
y' = re^rt
y''= r^2e^rt
4r^2 + 12r +9r = 0
r = -(2/3)
thus
y = c1e^(-(2/3))t + tc1e^(-(2/3))t
Logged
Print
Pages: [
1
]
« previous
next »
Toronto Math Forum
»
MAT244--2019F
»
MAT244--Test & Quizzes
»
Quiz-4
»
Quiz 4 TUT0202