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Term Test 1 / Re: TT1 = Problem 5
« on: October 16, 2012, 08:16:11 PM »Solution is attached,
Aida, I think your solution is not correct - the integral from -1 to 0 will only be 0 if x < y in H(x-y), i.e. x < -1.
Also, consider extreme cases - for C(-100), H(-100-y) can never be greater than 0, so a solution with C(x) = 1 cannot be right (unless I've totally misunderstood something).
I believe your solution is not correct; H(x) and H(x-y) has the same value for these two different domain because it is a constant function.