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### Messages - Jiabei Bi

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1
##### Quiz-7 / Re: Q7 TUT 5101
« on: November 30, 2018, 04:42:01 PM »
Here are my solutions

2
##### Term Test 2 / Re: TT2A-P1
« on: November 20, 2018, 12:34:21 PM »

3
##### Quiz-4 / Re: Q4 TUT 0501
« on: October 26, 2018, 08:59:47 PM »
The file is too large to upload. So I upload two files.

4
##### Quiz-4 / Re: Q4 TUT 0601
« on: October 26, 2018, 08:15:18 PM »
here is my solution

5
##### Term Test 1 / Re: TT1 Problem 1 (afternoon)
« on: October 16, 2018, 09:41:48 AM »
here is my solution

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##### Quiz-1 / Re: Q1: TUT0301
« on: September 28, 2018, 06:00:22 PM »
I have a question for the first example from last night’s lecture. The condition is $y’=y²$ , $y(0) = 1$. I know how to get the solution. The answer is $y =1/(1-t)$. But I am confused about the restriction of variable $t$. Why the variable t has to be less than $1$?