Toronto Math Forum

MAT244--2019F => MAT244--Test & Quizzes => Quiz-3 => Topic started by: Hongling Liu on October 11, 2019, 02:02:10 PM

Title: quiz3 0501
Post by: Hongling Liu on October 11, 2019, 02:02:10 PM

    y‘’ - 2y’ - 2y = 0
    Solution:
    r^2 - 2r - 2= 0
    r1 = 1 +√3
    r2 = 1- √3
    y = C1⋅e^(1+√3)⋅t + C2⋅e^(1-√3)⋅t