Toronto Math Forum
Welcome,
Guest
. Please
login
or
register
.
1 Hour
1 Day
1 Week
1 Month
Forever
Login with username, password and session length
News:
Home
Help
Search
Calendar
Login
Register
Toronto Math Forum
»
MAT244--2019F
»
MAT244--Test & Quizzes
»
Quiz-3
»
TUT 0701 Quiz 3
« previous
next »
Print
Pages: [
1
]
Author
Topic: TUT 0701 Quiz 3 (Read 6474 times)
maoyafei
Newbie
Posts: 4
Karma: 0
TUT 0701 Quiz 3
«
on:
October 13, 2019, 11:51:38 PM »
Find the general solution of the given differential equation
y''+3y'+2y=0
assume y=e^(rt), y'=re^(rt), y''=(r^2)e^(rt)
r^2+3r+2
(r+1)(r+2)=0
r1=-1, r2=-2
y=C1e^(r1t)+C2e^(r2t)
Ans: y=C1e^(-t) + C2e^(-2t)
«
Last Edit: October 13, 2019, 11:54:03 PM by maoyafei
»
Logged
Print
Pages: [
1
]
« previous
next »
Toronto Math Forum
»
MAT244--2019F
»
MAT244--Test & Quizzes
»
Quiz-3
»
TUT 0701 Quiz 3