The limit does not exist.
By definition of limit as $z\to\infty$,
$$\lim_{z\to\infty} h(z) =\lim_{z\to\infty} \frac{|z|}{z} = \lim_{z\to 0} \frac{|\frac{1}{z}|}{\frac{1}{z}} =\lim_{z\to 0} \frac{\frac{1}{|z|}}{\frac{1}{z}} = \lim_{z\to 0} \frac{z}{|z|} $$
Let $z = x + iy$, then
$$\lim_{z\to\infty} h(z) = \lim_{(x,y)\to (0,0)} \frac{x+iy}{\sqrt{x^2+y^2}} = \lim_{(x,y)\to (0,0)} \frac{x}{\sqrt{x^2+y^2}} + i\frac{y}{\sqrt{x^2+y^2}} $$
Note that $ \lim_{(x,y)\to (0,0)} \frac{x}{\sqrt{x^2+y^2}} $ does not exist since $$ \lim_{(x,y)\to (0,0)} \frac{x}{\sqrt{x^2+y^2}} = 1 $$ when $z$ approaches 0 alone the positive real axis, and $$ \lim_{(x,y)\to (0,0)} \frac{x}{\sqrt{x^2+y^2}} = -1 $$ when $z$ approaches 0 alone the negative real axis.
Similarly, $ \lim_{(x,y)\to (0,0)} \frac{y}{\sqrt{x^2+y^2}} $ does not exist.
This implies that $\lim_{z\to\infty} h(z)$ does not exist.
